A wire of resistance 20Ω is bent in the form of a square. The resistance between the ends of diagonal is:
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Correct option is B)
Since the wire is bend in form of the square and we know that sides of square are equal so each side will have same resistance i.e 5 ohm. Now if we make diagonal two faces in each side of the diagonal will have two sides and resistance will be 10 ohm.
R=20Ω So, 4R=5Ω ⇒R1=10Ω; R2=10Ω So, resistance between the ends of a diagonal = RD=2×1010×10Ω=5Ω