A wood 1 cm thick required to a box of dimensions 24 cm times 22 cm times 17 cm- is2500 cm-32600 cm-32276 cm-32376 cm-3

Question

Toppr Admin · Accepted Answer

Outer volume of the box -24-xD7-22-xD7-17-8976-xA0-cm3Inner volume of the box-xA0-24-x2212-2-xD7-22-x2212-2-xD7-17-x2212-2-22-xD7-20-xD7-15-6600-xA0-cm3Therefore- the wood required-8976-x2212-6600-2376-xA0-cm3Hence- this is the answer-

A wood 1 cm thick required to make a box of dimensions $24 c m \times 22 c m \times 17 c m$ , is
$2500 c m^{3}$
$2600 c m^{3}$
$2276 c m^{3}$
$2376 c m^{3}$

Outer volume of the box $= 24 \times 22 \times 17 = 8976 c m^{3}$
Inner volume of the box
$= (24 - 2) \times (22 - 2) \times (17 - 2)$
$= 22 \times 20 \times 15 = 6600 c m^{3}$

Therefore, the wood required
$= 8976 - 6600 = 2376 c m^{3}$

Hence, this is the answer.

A wood 1 cm thick required to make a box of dimensions 24cm×22cm×17cm, is2500cm32600cm32276cm32376cm3

Outer volume of the box =24×22×17=8976 cm3Inner volume of the box =(24−2)×(22−2)×(17−2)=22×20×15=6600 cm3Therefore, the wood required=8976−6600=2376 cm3Hence, this is the answer.

A wood 1 cm thick required to make a box of dimensions $24 c m \times 22 c m \times 17 c m$ , is
$2500 c m^{3}$
$2600 c m^{3}$
$2276 c m^{3}$
$2376 c m^{3}$

Outer volume of the box $= 24 \times 22 \times 17 = 8976 c m^{3}$
Inner volume of the box
$= (24 - 2) \times (22 - 2) \times (17 - 2)$
$= 22 \times 20 \times 15 = 6600 c m^{3}$

Therefore, the wood required
$= 8976 - 6600 = 2376 c m^{3}$

Hence, this is the answer.