A Zener diode- having breakdown voltage equal to 15 V is used in a voltage regulator circuit shown in figure- The current through the diode is10 mA15 mA20 mA5 mA

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Toppr Admin · Accepted Answer

For R-1k-x3A9-i1-151mA-15mAR-250-x3A9-i250-20-x2212-15250-5250-20mAiZener-20-x2212-15-5mA

A Zener diode, having breakdown voltage equal to $15 V$ is used in a voltage regulator circuit shown in figure. The current through the diode is

$10 m A$
$15 m A$
$20 m A$
$5 m A$

For $R = 1 k Ω$
$i_{1} = \frac{15}{1} m A = 15 m A$
$R = 250 Ω$
$i_{250} = \frac{20 - 15}{250} = \frac{5}{250} = 20 m A$
$i_{Z e n e r} = 20 - 15 = 5 m A$

A Zener diode, having breakdown voltage equal to 15V is used in a voltage regulator circuit shown in figure. The current through the diode is10mA15mA20mA5mA

For R=1kΩi1=151mA=15mAR=250Ωi250=20−15250=5250=20mAiZener=20−15=5mA

A Zener diode, having breakdown voltage equal to $15 V$ is used in a voltage regulator circuit shown in figure. The current through the diode is

$10 m A$
$15 m A$
$20 m A$
$5 m A$

For $R = 1 k Ω$
$i_{1} = \frac{15}{1} m A = 15 m A$
$R = 250 Ω$
$i_{250} = \frac{20 - 15}{250} = \frac{5}{250} = 20 m A$
$i_{Z e n e r} = 20 - 15 = 5 m A$