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AABC and \( \triangle D B C \) are two isosceles triangles on the same bise \( B C \) and vertices \( A \) and \( D \) are on
the same side of \( B C \) (see the given figure). If \( A D \) is extended to intersect \( B C \) at \( P \) , show that (iv) AP is the perpendicular bisector of BC.
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Q1
△ABC and △DBC are two isosceles triangle on the same base BC and vertices A and D are on the same side of BC (see figure). If AD is extended to intersect BC at P show that AP is the perpendicular bisector of BC
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Q2
Question 1 (iv)
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Q5
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