AB and CD are two chords of a circle which intersect each other internally P- If CP-4 cm- AP-8 cm- PB - 2 cm- then PD-

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Toppr Admin · Accepted Answer

Given- CP-4 cm- AP-8 cm and PB-2 cm-Let PD-xWe have AP-xD7-PB-CP-xD7-PD-x21D2-8-xD7-2-4-xD7-x-x21D2-16-4x -xA0- -xA0- -xA0- -xA0- -xA0-xA0-x21D2-x-4 -xA0- -xA0- -xA0- -xA0- -xA0-xA0-Thus- PD-4 cm

$A B$ and $C D$ are two chords of a circle which intersect each other internally at $P$ . If $C P = 4$ cm, $A P = 8$ cm, $P B = 2$ cm, then find $P D$ .

Given, $C P = 4$ cm, $A P = 8$ cm and $P B = 2$ cm.
Let $P D = x$
We have $A P \times P B = C P \times P D$
$\Rightarrow 8 \times 2 = 4 \times x$
$\Rightarrow 16 = 4 x$
$\Rightarrow x = 4$
Thus, $P D = 4$ cm

AB and CD are two chords of a circle which intersect each other internally at P. If CP=4 cm, AP=8 cm, PB=2 cm, then find PD.

Given, CP=4 cm, AP=8 cm and PB=2 cm.Let PD=xWe have AP×PB=CP×PD⇒8×2=4×x⇒16=4x ⇒x=4 Thus, PD=4 cm

$A B$ and $C D$ are two chords of a circle which intersect each other internally at $P$ . If $C P = 4$ cm, $A P = 8$ cm, $P B = 2$ cm, then find $P D$ .

Given, $C P = 4$ cm, $A P = 8$ cm and $P B = 2$ cm.
Let $P D = x$
We have $A P \times P B = C P \times P D$
$\Rightarrow 8 \times 2 = 4 \times x$
$\Rightarrow 16 = 4 x$
$\Rightarrow x = 4$
Thus, $P D = 4$ cm