Solve
Study
Textbooks
Guides
Use app
Login
Question
AB and CD are two slabs. The medium between the slabs has refractive index 2. Find the minimum angle of incidence at Q so that the ray is totally reflected by both the slabs
A
60
∘
B
45
∘
C
30
∘
D
75
∘
Medium
Open in App
Solution
Verified by Toppr
Correct option is A)
θ
c
r
i
c
m
1
m
2
=
s
i
n
−
1
(
2
3
)
=
6
0
0
θ
c
r
i
c
m
2
m
3
=
s
i
n
−
1
(
2
1
)
=
4
5
0
θ
≥
6
0
0
Was this answer helpful?
0
0
Similar questions
The minimum refractive index of the prism given
below should be:
Medium
View solution
>
For total internal reflection to take place, the angle of incidence
i
and the refractive index
μ
of the medium must satisfy the inequality
Easy
View solution
>
A ray of light travelling in a transparent medium of refractive index falls on a surface separating the medium from the air at an angle of incidence of 45. For which of the following values of the ray can undergo total internal reflection?
Medium
View solution
>
A light ray moving in medium - I (of refractive index
n
1
) is incident on interface of two media and it is totally internally reflected at the interface. Now, refractive index
n
2
of medium - II is decreased, then:
Hard
View solution
>
A beam of light passes through a sheet of plastic and out into the air. The beam makes
θ
1
angles with the normal as it passes through the plastic and the angle the beam of light makes with the normal as it passes into the air is
θ
2
. The refractive index for air is
1
and
The refractive index
for plastic is
2
.
Find out the minimum incident angle for which the light will undergo total internal reflection in the plastic?
Medium
View solution
>