AB band CD bisect each other K- Prove that AC-BD

Question

Toppr Admin · Accepted Answer

As AB and CD bisect each other-x21D2-AK-BK-CK-DKalso -x2220-AKC-x2220-BKD-x21D2-x25B3-AKC-x2245-x25B3-BKD by SAS congrueney-x21D2-AC-BD by C-P-C-T- -corresponding parts of congruent triangles-

$A B$ band $C D$ bisect each other at $K$ . Prove that $A C = B D$

As $A B$ and $C D$ bisect each other
$\Rightarrow A K = B K, C K = D K$
also $∠ A K C = ∠ B K D$
$\Rightarrow △ A K C ≅ △ B K D$ by SAS congrueney
$\Rightarrow A C = B D$ by C.P.C.T. (corresponding parts of congruent triangles)

AB band CD bisect each other at K. Prove that AC=BD

As AB and CD bisect each other⇒AK=BK,CK=DKalso ∠AKC=∠BKD⇒△AKC≅△BKD by SAS congrueney⇒AC=BD by C.P.C.T. (corresponding parts of congruent triangles)

$A B$ band $C D$ bisect each other at $K$ . Prove that $A C = B D$

As $A B$ and $C D$ bisect each other
$\Rightarrow A K = B K, C K = D K$
also $∠ A K C = ∠ B K D$
$\Rightarrow △ A K C ≅ △ B K D$ by SAS congrueney
$\Rightarrow A C = B D$ by C.P.C.T. (corresponding parts of congruent triangles)