Question

From the given diagram, in which $ABCD$ is a parallelogram, $ABL$ is a line segment and E is mid point of BC. Hence, $AB = BL.$

If the above statement is true then mention answer as 1, else mention 0 if false

Answer 1

Given, $ABCD$ is a parallelogram. $E$ is mid point of $BC.$

Now, In $△CED$ and $△BEL$

$\angle CED=\angle BEL$(Vertically opposite angle

s)
$EC=BE$ (Given, E is mid point of BC)

$\angle DCE=\angle EBL$ (Alternate angles)

Thus, $△CED\cong △BEL$ (SAS rule)

Hence, $CD=BL$ (By cpct)

Since, $CD=AB$ (ABCD is a parallelogram)

Thus, $CD=BL=AB$