AB is a line segment.P and Q are points on oposite sides of AB such that each of them is equidistant from the points A and B.Show that △PAQ≅△PBQ
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Solution
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In △PAQ and △PBQ
PA=PB(given)
QA=QB(given)
PQ=PQ(common)
So,△PAQ≅△PBQ by SSS rule.
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