maths

If the above statement is true then mention answer as 1, else mention 0 if false

In $△$ ABO and $△$ ACO,

AB = AC (Given)

$∠ABO=∠ACO$ (ABD is an isosceles tiangle)

AO = AO (Common side)

$∴$ $△ABO≅△ACO$ (By SSA congruence rule)

Hence, $∠AOB=∠AOC=x$ (Corresponding angles of congruent triangles)

Now, $∠AOB+∠AOC=180$

$x+x=180$

$x=90$

Thus, AD bisects BC at right angles.

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State the congruency of following pair of triangles.

In $ΔABC$ and $ΔDEF$, AB = DE, BC = DE, BC = EF and $∠B=∠E$.

Answer: By SAS

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(i) $OB=OC$ (ii) $AO$ bisects $∠A$

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