ABCD is a parallelogram of area 162- cm-2- P is a point on AB such that AP - PB - 1 - 2- Calculate the area of Delta APD20- cm-227 cm-224 cm-225 cm-2

Question

Toppr Admin · Accepted Answer

If DB is the diagonal-Area of parallelogram 12ABCD-xA0-area ADB-xA0-area BDCArea ADB-12-162-81P is mid point of AB in the ratio 1-2 -13-23-xA0-Area APD -13-xD7- Area of ADB-13-81-27 sq- cm

$A B C D$ is a parallelogram of area $162 c m^{2}$ . $P$ is a point on $A B$ such that $A P : P B = 1 : 2$ . Calculate the area of $Δ A P D$

$20 c m^{2}$
$27 c m^{2}$
$24 c m^{2}$
$25 c m^{2}$

If $D B$ is the diagonal,
Area of parallelogram $\frac{1}{2} A B C D =$ area $A D B =$ area $B D C$
Area ADB $= \frac{1}{2} (162) = 81$
$P$ is mid point of $A B$ in the ratio $1 : 2$ $(\frac{1}{3} + \frac{2}{3})$
Area APD $= \frac{1}{3} \times$ Area of $A D B = \frac{1}{3} (81) = 27$ sq. cm

ABCD is a parallelogram of area 162cm2. P is a point on AB such that AP:PB=1:2. Calculate the area of ΔAPD20cm227 cm224 cm225 cm2

If DB is the diagonal,Area of parallelogram 12ABCD= area ADB= area BDCArea ADB=12(162)=81P is mid point of AB in the ratio 1:2 (13+23) Area APD =13× Area of ADB=13(81)=27 sq. cm

$A B C D$ is a parallelogram of area $162 c m^{2}$ . $P$ is a point on $A B$ such that $A P : P B = 1 : 2$ . Calculate the area of $Δ A P D$

$20 c m^{2}$
$27 c m^{2}$
$24 c m^{2}$
$25 c m^{2}$

If $D B$ is the diagonal,
Area of parallelogram $\frac{1}{2} A B C D =$ area $A D B =$ area $B D C$
Area ADB $= \frac{1}{2} (162) = 81$
$P$ is mid point of $A B$ in the ratio $1 : 2$ $(\frac{1}{3} + \frac{2}{3})$
Area APD $= \frac{1}{3} \times$ Area of $A D B = \frac{1}{3} (81) = 27$ sq. cm