ABCD is a quadrilateral with angle A - 80-circ- angle B - 40-circ- angle C - 140-circ- angle D - 100-circ-i- Is ABCD is trapezium- -ii- Is ABCD is parallelogram-Justify your answer-

Question

Toppr Admin · Accepted Answer

ABCD-xA0- is neither a parallelogram nor a trapezium - It can be justified using basic sum property of co-interior angles to be 180 of parallel lines -

$A B C D$ is a quadrilateral with $∠ A = 80^{\circ}, ∠ B = 40^{\circ}, ∠ C = 140^{\circ}, ∠ D = 100^{\circ}$ .
(i) Is $A B C D$ is trapezium? (ii) Is $A B C D$ is parallelogram?
Justify your answer.

ABCD is neither a parallelogram nor a trapezium . It can be justified using basic sum property of co-interior angles to be 180 of parallel lines .

ABCD is a quadrilateral with ∠A=80∘,∠B=40∘,∠C=140∘,∠D=100∘.(i) Is ABCD is trapezium? (ii) Is ABCD is parallelogram?Justify your answer.

ABCD is neither a parallelogram nor a trapezium . It can be justified using basic sum property of co-interior angles to be 180 of parallel lines .

$A B C D$ is a quadrilateral with $∠ A = 80^{\circ}, ∠ B = 40^{\circ}, ∠ C = 140^{\circ}, ∠ D = 100^{\circ}$ .
(i) Is $A B C D$ is trapezium? (ii) Is $A B C D$ is parallelogram?
Justify your answer.