ABCD is a square of area of 4 square which is divided into 4 non overlapping triangles as shown in figure- then of perimeters of the triangles so formed is8 - 2 - sqrt - 2 - -8 - 1 - sqrt - 2 - -4 - 1 - sqrt - 2 - -4 - 2 - sqrt - 2 - -

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ABCD is a square of area of 4 square units which is divided into 4 non overlapping triangles as shown in figure, then sum of perimeters of the triangles so formed is8(2+√2)8(1+√2)4(1+√2)4(2+√2)

$A B C D$ is a square of area of 4 square units which is divided into 4 non overlapping triangles as shown in figure, then sum of perimeters of the triangles so formed is

$8 (2 + \sqrt{2})$
$8 (1 + \sqrt{2})$
$4 (1 + \sqrt{2})$
$4 (2 + \sqrt{2})$