ABCD is a square; X is the mid-point of AB and Y the mid-point of BC . Hence, The triangles ADX and BAY are congruent If the above statement is true then mention answer as 1, else mention 0 if false
Open in App
Solution
Verified by Toppr
AB=BC (ABCD is a square) 12AB=12BC AX=BY (X and Y are mid points of AB and BC respectively) In △AXD and △ABY, ∠DAX=∠ABY (Each 90∘) AX=BY (Proved above) AD=AB (ABCD is a square) Thus, △AXD≅△BYA
Was this answer helpful?
0
Similar Questions
Q1
ABCD is a square; X is the mid-point of AB and Y the mid-point of BC . Hence, The triangles ADX and BAY are congruent If the above statement is true then mention answer as 1, else mention 0 if false
View Solution
Q2
Quadrilateral ABCD is a square. X is the mid-point of AB and Y is the mid-point of BC. Hence, ∠DXA=∠AYB
If the above statement is true then mention answer as 1, else mention 0 if false
View Solution
Q3
ABCD is a square; X is the mid-point of AB and Y the mid-point of BC.Hence, DX is perpendicular to AY.
If the above statement is true then mention answer as 1, else mention 0 if false.
View Solution
Q4
From the given diagram, in which ABCD is a parallelogram, ABL is a line segment and E is mid point of BC. Hence, $AB = BL.$
If the above statement is true then mention answer as 1, else mention 0 if false
View Solution
Q5
ABCD is a square P,Q and R are the points on AB, BC and CD respectively; such that AP=BQ=CR. Hence, PB=QC If the above statement is true then mention answer as 1, else mention 0 if false