0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

ABCD is a trapezium in which \( A B \) II CD and \( \mathrm { AD } = \mathrm { BC } \) (see Fig. 8.23 ) . Show that (1) \( \quad \angle A = \angle B \) \( \angle C = \angle D \) (iii) \( \Delta \mathrm { ABC } = \mathrm { ABAD } \) (iv) diagonal \( A C = \) diagonal \( B D \) IHint: Bxtend AB and draw a line through \( c \) parallel to DA intersecting AB produced al E.

Solution
Verified by Toppr


Was this answer helpful?
0
Similar Questions
Q1

ABCD is a trapezium in which AB || CD and AD = BC (see the given figure). Show that

(i) āˆ A = āˆ B

(ii) āˆ C = āˆ D

(iii) Ī”ABC ā‰… Ī”BAD

(iv) diagonal AC = diagonal BD

[Hint: Extend AB and draw a line through C parallel to DA intersecting AB produced at E.]

View Solution
Q2
ABCD is a trapezium in which ABCD and AD=BC (see figure). Show that
(i) A=B
(ii) C=D
(iii) ABCBAD
(iv) diagonal AC= diagonal BD
1177783_2723aa13532049e39375d72552aba78f.png
View Solution
Q3

ā–”ABCD is a trapezium in which AB||CD andAD=BC(see Fig.) . Show that āˆ C=āˆ D ( [Hint : Extend AB and draw a line through Cparallel to DA intersecting AB produced at E.]


View Solution
Q4
ABCD is a trapezium in which ABDC,BD is a diagonal and E is the mid-point of AD. A line is drawn through E parallel to AB, intersecting BC at F (see Fig). Show that F is the mid-point of BC.
463892_2f41f39ff3704fd790bc8e856fef02e5.png
View Solution
Q5
In given figure ABCD is a trapezium in which ABCD and AD=BC. Show that
(i) A=B
(ii) C=D
(iii) ABCBAD
(iv) diagonal AC= diagonal BD
463886.jpg
View Solution