A,B,C,D,P and Q are points in uniform electric field. The potentials at these points are V(A)=2volt. V(P)=V(B)=V(D)=+5volt. V(C)=8volt. The electric field at P is:

10Vm−1 along PQ

5Vm−1 along PC

15√2Vm−1 along PA

5Vm−1along PA

A

10Vm−1 along PQ

B

15√2Vm−1 along PA

C

5Vm−1 along PC

D

5Vm−1along PA

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Solution

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Electric field E=−dVdx−dVdy=−ΔVΔx−ΔVΔy Ex=−VD−VAxD−xA=−5−20.2=−15V/m

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