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Question

About 5% of the power of a 100 W light bulb is converted to visible radiation. What is the average intensity of visible radiation
(a) at a distance of 1m from the bulb?
(b) at a distance of 10 m?

Assume that the radiation is emitted isotropically and neglect reflection.

Solution
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(a)
Power of visible radiation P=5×100/100=5W
I=P/4πd2=0.398W/m2; d=1m

(b)

Power of visible radiation P=5×100/100=5W

I=P/4πd2=0.004W/m2; d=10m

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