Acetaldehyde and benzaldehyde can be differentiated by :

Question

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Answer 1

(Refer to Image 1)
For iodoform test one methyl must be there with carbonyl group. Thus acetaldehyde will give iodoform test and benzaldehyde does not.
(Refer to Image 2)
In Fehling test, enolate formation takes place, thus Aldehydes that lack alpha hydrogen cannot form an enolate and thus do not give a positive Fehling's test.
Thus Benzaldehyde do not give Fehling test as it do not have $α -$ Hydrogen. While Acetaldehyde have $3 α -$ Hydrogen thus it can form enolate and undergo Fehling test.
Thus Benzaldehyde & Acetaldehyde can be differentiated using Iodoform and Fehling test.

Answer 2

(Refer to Image 1)

For iodoform test one methyl must be there with carbonyl group. Thus acetaldehyde will give iodoform test and benzaldehyde does not.

(Refer to Image 2)

In Fehling test, enolate formation takes place, thus Aldehydes that lack alpha hydrogen cannot form an enolate and thus do not give a positive Fehling's test.

Thus Benzaldehyde do not give Fehling test as it do not have

α -

Hydrogen. While Acetaldehyde have

3 α -

Hydrogen thus it can form enolate and undergo Fehling test.

Thus Benzaldehyde & Acetaldehyde can be differentiated using Iodoform and Fehling test.

Acetaldehyde and benzaldehyde can be differentiated by :

Fehling test

Iodoform test

Tollen's reagent

both (a) and (b)

The reagent which does not react with both, acetone and benzaldehyde is:

Acetaldehyde reduces Fehling's solution but benzaldehyde does not.

Acetaldehyde is stronger reducing agent than benzaldehyde.

Fehling's solution can be used to distinguish benzaldehyde from acetaldehyde.

Both benzaldehyde and acetaldehyde reduces Tollen's reagent.

Above compounds can be differentiated by using the reagent:

The reagent used to distinguish between acetaldehyde and benzaldehyde is :