AD is an altitude of an isosceles triangles ABC in which AB $=$ AC. Show that AD bisects $∠$ A.

Open in App

Solution

Verified by Toppr

Was this answer helpful?

Similar Questions

AD is an altitude of an isosceles triangle ABC in which AB

=

AC. Show that AD bisects

∠

View Solution

AD is an altitude of an isosceles triangles ABC in which AB = AC. Show that

(i) AD bisects BC (ii) AD bisects ∠A.

View Solution

A D

is an altitude of an isosceles triangle

A B C

in which

A B = A C

.
Show that,

A D

bisects

B C

View Solution

AD is an altitude of an isosceles triangle ABC in which AB=AC show that, (i) AD bisects BC (ii) AD bisects

∠ A

View Solution

Question 2 (ii)
AD is an altitude of an isosceles triangles ABC in which AB = AC.
Show that AD bisects $∠ A$ .

View Solution

AD is an altitude of an isosceles triangles ABC in which AB=AC. Show that AD bisects ∠A.