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Question

Add $$ 1 \dfrac{1}{4} $$ and $$ 6 \dfrac{1}{2} $$.

Solution
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We have:. $$ 1\dfrac {1}{4} = \dfrac {( 1\times 4) +1 }{ 4}=\dfrac {5}{4} $$
And $$ 6 \dfrac {1}{2} =\dfrac {( 6 \times 2) + 1}{2} =\dfrac {13}{2}$$

$$ \therefore\ 1 \dfrac{1}{4} + 6 \dfrac{1}{2}= \dfrac {5}{4}+\dfrac {13}{2}\\ =\dfrac {5}{4}\times\dfrac11+\dfrac {13}{2}\times\dfrac22\\=\dfrac {5}{4}+\dfrac {26}4\\=\dfrac {31}4=7\dfrac 34$$

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