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Standard VI
Mathematics
Addition of Fractions
Question
Add
1
3
4
,
2
1
10
,
3
1
3
.
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Solution
Verified by Toppr
⇒
Here Summation will be S,
S
=
1
3
4
+
2
1
10
+
3
1
3
now, we can write mixed function as below,
a
b
c
=
a
c
+
b
c
=
a
+
b
c
So,
S
=
1
+
3
4
+
2
+
1
10
+
3
+
1
3
=
6
+
3
4
+
1
10
+
1
3
(take LCM of 4, 10, 3, we get 60).
=
6
+
3
(
15
)
+
1
(
6
)
+
1
(
20
)
60
=
6
+
45
+
6
+
20
60
=
6
+
71
60
=
6
+
60
+
11
60
=
6
+
1
+
11
60
=
7
+
11
60
=
7
11
60
So,
1
3
4
+
2
1
10
+
3
1
3
=
7
11
60
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Q2
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