Add the following rational numbers-dfrac -6-11- and dfrac -4-11-

Question

Toppr Admin · Accepted Answer

Let-160-us add the fractions -dfrac -6-11- - -dfrac -4-11-Since it has the same denominators we can add directly- -dfrac -6 - -4-11-The multiplication of - - is - -therefore- We get- -dfrac -6 - 4-11-Rightarrow -dfrac -10-11-

Add the following rational numbers:
$$\dfrac {-6}{11}$$ and $$\dfrac {-4}{11}$$.

Let us add the fractions $$\dfrac {-6}{11} + \dfrac {-4}{11}$$
Since it has the same denominators we can add directly, $$\dfrac {-6 + (-4)}{11}$$
The multiplication of $$(+) (-)$$ is $$(-). \therefore$$ We get, $$\dfrac {-6 - 4}{11}\Rightarrow \dfrac {-10}{11}$$.

Add the following rational numbers:$$\dfrac {-6}{11}$$ and $$\dfrac {-4}{11}$$.

Let us add the fractions $$\dfrac {-6}{11} + \dfrac {-4}{11}$$Since it has the same denominators we can add directly, $$\dfrac {-6 + (-4)}{11}$$The multiplication of $$(+) (-)$$ is $$(-). \therefore$$ We get, $$\dfrac {-6 - 4}{11}\Rightarrow \dfrac {-10}{11}$$.

Add the following rational numbers:
$$\dfrac {-6}{11}$$ and $$\dfrac {-4}{11}$$.

Let us add the fractions $$\dfrac {-6}{11} + \dfrac {-4}{11}$$
Since it has the same denominators we can add directly, $$\dfrac {-6 + (-4)}{11}$$
The multiplication of $$(+) (-)$$ is $$(-). \therefore$$ We get, $$\dfrac {-6 - 4}{11}\Rightarrow \dfrac {-10}{11}$$.