Addition of excess potassium iodide solution to a solution of mercuric chloride gives the halide complex :
tetrahedral $K_{2} [H g I_{4}]$
linear ${H g}_{2} I_{2}$
trigonal $K_{2} [H g I_{3}]$
square planar $K_{2} [H g {C l}_{2} I_{2}]$

Question

Addition of excess potassium iodide solution to a solution of mercuric chloride gives the halide complex -tetrahedral -K-2-Hg-I-4-linear -Hg-2-I-2-trigonal -K-2-Hg-I-3-square planar -K-2-Hg-Cl-2-I-2-

Toppr Admin · Accepted Answer

-x394-H-0-HgCl2-4KI-x27F6-K2-HgI4-2KClHg-Xe-4f145d106s2Hg2-Xe-4f145d106s0Hence- the correct option is A

Addition of excess potassium iodide solution to a solution of mercuric chloride gives the halide complex :tetrahedral K2[HgI4]linear Hg2I2trigonal K2[HgI3]square planar K2[HgCl2I2]

ΔH=0,HgCl2+4KI⟶K2[HgI4]+2KClHg=[Xe]4f145d106s2Hg2+=[Xe]4f145d106s0Hence, the correct option is A

Addition of excess potassium iodide solution to a solution of mercuric chloride gives the halide complex :
tetrahedral $K_{2} [H g I_{4}]$
linear ${H g}_{2} I_{2}$
trigonal $K_{2} [H g I_{3}]$
square planar $K_{2} [H g {C l}_{2} I_{2}]$

$Δ H = 0, H g {C l}_{2} + 4 K I ⟶ K_{2} [H g I_{4}] + 2 K C l$

$H g = [X e] 4 f^{14} 5 d^{10} 6 s^{2}$

${H g}^{2 +} = [X e] 4 f^{14} 5 d^{10} 6 s^{0}$

Hence, the correct option is $A$