Adsorption of a gas follows Freundlich adsorption isotherm.
$x$ is the mass of the gas adsorbed on mass $m$ of the adsorbent.

The plot of $log (\frac{x}{m})$ versus $log P$ is shown in the graph. $(\frac{x}{m})$ is proportional to:

Question

Adsorption of a gas follows Freundlich adsorption isotherm.

x

is the mass of the gas adsorbed on mass

m

of the adsorbent.

The plot of

log (\frac{x}{m})

versus

log P

is shown in the graph.

(\frac{x}{m})

is proportional to:

Toppr Admin · Accepted Answer

Correct option is C- -p-2-3-Solution- -C- -p-2-3-dfrac-x-m-K-p-1-n-therefore log -dfrac-x-m-log K-dfrac-1-n- log P-slope -dfrac-1-n-dfrac-2-3-therefore -dfrac-x-m-K-p-2-3-

Adsorption of a gas follows Freundlich adsorption isotherm $$x$$ is the mass of the gas adsorbed on mass $$m$$ of the adsorbent. The plot of log $$\dfrac{x}{m}$$ versus log $$p$$ is shown in the given graph. $$\dfrac{x}{m}$$ is proportional to :

Correct option is C. $$p^{2/3}$$
Solution:- (C) $${p}^{{2}/{3}}$$

$$\dfrac{x}{m}=K.p^{1/n}$$

$$\therefore log \dfrac{x}{m}=log K+\dfrac{1}{n}. log P$$

slope $$=\dfrac{1}{n}=\dfrac{2}{3}$$

$$\therefore \dfrac{x}{m}=K.p^{2/3}$$

Adsorption of a gas follows Freundlich adsorption isotherm $$x$$ is the mass of the gas adsorbed on mass $$m$$ of the adsorbent. The plot of log $$\dfrac{x}{m}$$ versus log $$p$$ is shown in the given graph. $$\dfrac{x}{m}$$ is proportional to :

Correct option is C. $$p^{2/3}$$Solution:- (C) $${p}^{{2}/{3}}$$$$\dfrac{x}{m}=K.p^{1/n}$$$$\therefore log \dfrac{x}{m}=log K+\dfrac{1}{n}. log P$$slope $$=\dfrac{1}{n}=\dfrac{2}{3}$$$$\therefore \dfrac{x}{m}=K.p^{2/3}$$

Correct option is C. $$p^{2/3}$$
Solution:- (C) $${p}^{{2}/{3}}$$

$$\dfrac{x}{m}=K.p^{1/n}$$

$$\therefore log \dfrac{x}{m}=log K+\dfrac{1}{n}. log P$$

slope $$=\dfrac{1}{n}=\dfrac{2}{3}$$

$$\therefore \dfrac{x}{m}=K.p^{2/3}$$