Adsorption of a gas on solid metal surface is spontaneous and exothermic, then :
ΔH increases
ΔS increases
ΔG increases
ΔS decreases
A
ΔS increases
B
ΔG increases
C
ΔH increases
D
ΔS decreases
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Solution
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Adsorption of a gas on solid metal surface is spontaneous and exothermic, then ΔS decreases.
Since for spontaneous and exothermic process, ΔG=−ve,ΔH=−ve at all temperatures.
Therefore, from ΔG=ΔH−TΔS,ΔS should be −ve.
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