After completion of ‘np’ level, the electron enters into which level according to (n+p) rule?
(n−1)d
(n+1)p
nd
(n+1)s
A
(n−1)d
B
(n+1)p
C
(n+1)s
D
nd
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Solution
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Energy of nd level would be higher than (n+1)s. nd=n+2, (n+1)s=n+1. So, electron will enter into lower energy level. i.e, (n+1)s
Let us take an example of ′4p′ orbital. As per Moeller diagram, the orbital that will be filled after ′4p′ orbital is ′5s′. Hence, (n+1)s orbital will be filled after ′np′ orbital.
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