After rationalising the denominator of dfrac-7-3sqrt-3-2sqrt-2- we get the denominator of the resultant equivalent expression as-5131935

Question

Toppr Admin · Accepted Answer

73-x221A-3-x2212-2-x221A-2-73-x221A-3-x2212-2-x221A-2-xD7-3-x221A-3-2-x221A-23-x221A-3-2-x221A-2-7-3-x221A-3-2-x221A-2-27-x2212-8-7-3-x221A-3-2-x221A-2-19- Hence- the denominator of the equivalent expression is 19-

After rationalising the denominator of $\frac{7}{3 \sqrt{3} - 2 \sqrt{2}}$ , we get the denominator of the resultant equivalent expression as:
$5$
$13$
$19$
$35$

$\frac{7}{3 \sqrt{3} - 2 \sqrt{2}} = \frac{7}{3 \sqrt{3} - 2 \sqrt{2}} \times (\frac{3 \sqrt{3} + 2 \sqrt{2}}{3 \sqrt{3} + 2 \sqrt{2}}) = \frac{7 (3 \sqrt{3} + 2 \sqrt{2})}{27 - 8} = \frac{7 (3 \sqrt{3} + 2 \sqrt{2})}{19}$ . Hence, the denominator of the equivalent expression is $19.$

After rationalising the denominator of 73√3−2√2, we get the denominator of the resultant equivalent expression as:5131935

73√3−2√2=73√3−2√2×(3√3+2√23√3+2√2)=7(3√3+2√2)27−8=7(3√3+2√2)19. Hence, the denominator of the equivalent expression is 19.

After rationalising the denominator of $\frac{7}{3 \sqrt{3} - 2 \sqrt{2}}$ , we get the denominator of the resultant equivalent expression as:
$5$
$13$
$19$
$35$

$\frac{7}{3 \sqrt{3} - 2 \sqrt{2}} = \frac{7}{3 \sqrt{3} - 2 \sqrt{2}} \times (\frac{3 \sqrt{3} + 2 \sqrt{2}}{3 \sqrt{3} + 2 \sqrt{2}}) = \frac{7 (3 \sqrt{3} + 2 \sqrt{2})}{27 - 8} = \frac{7 (3 \sqrt{3} + 2 \sqrt{2})}{19}$ . Hence, the denominator of the equivalent expression is $19.$