Air has three major components- nitrogen- oxygen- and argon- Given that one mole of air sea level is mole up of 78- nitrogen- 21- oxygen- and 1- argon- by volume- What is the density of air- Assume that gases behave in an ideal manner- -Atomic mass of argon is 40amu-1-291-981-62-3

Question

Toppr Admin · Accepted Answer

The correct option is A 1-291 mole of sample of air- means total volume- 22-4l0-78 mol N2-21-84gm N20-21 mol O2-6-72gm O20-01 mol Ar-0-4gm ArTotal mass- 28-96gmDensity- 28-9622-4-1-29gm-lit -

Air has three major components: nitrogen, oxygen, and argon. Given that one mole of air at sea level is mole up of $78$ nitrogen, $21$ oxygen, and $1$ argon, by volume. What is the density of air? Assume that gases behave in an ideal manner. (Atomic mass of argon is $40 a m u$ )
1.29
1.98
1.6
2.3

The correct option is A 1.29
$1$ mole of sample of air, means total volume= $22.4 l$
$0.78$ mol $N_{2} = 21.84 g m$ $N_{2}$
$0.21$ mol $O_{2} = 6.72 g m$ $O_{2}$
$0.01$ mol $A r = 0.4 g m$ $A r$
Total mass= $28.96 g m$
Density= $\frac{28.96}{22.4} = 1.29 g m / l i t$ .

Air has three major components: nitrogen, oxygen, and argon. Given that one mole of air at sea level is mole up of 78 nitrogen, 21 oxygen, and 1 argon, by volume. What is the density of air? Assume that gases behave in an ideal manner. (Atomic mass of argon is 40amu)1.291.981.62.3

The correct option is A 1.291 mole of sample of air, means total volume= 22.4l0.78 mol N2=21.84gm N20.21 mol O2=6.72gm O20.01 mol Ar=0.4gm ArTotal mass= 28.96gmDensity= 28.9622.4=1.29gm/lit .

Air has three major components: nitrogen, oxygen, and argon. Given that one mole of air at sea level is mole up of $78$ nitrogen, $21$ oxygen, and $1$ argon, by volume. What is the density of air? Assume that gases behave in an ideal manner. (Atomic mass of argon is $40 a m u$ )
1.29
1.98
1.6
2.3

The correct option is A 1.29
$1$ mole of sample of air, means total volume= $22.4 l$
$0.78$ mol $N_{2} = 21.84 g m$ $N_{2}$
$0.21$ mol $O_{2} = 6.72 g m$ $O_{2}$
$0.01$ mol $A r = 0.4 g m$ $A r$
Total mass= $28.96 g m$
Density= $\frac{28.96}{22.4} = 1.29 g m / l i t$ .