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Question

Air is filled in a tube of the wheel of a car at 27C and 2 atm pressure if the tube is suddenly bursts, the final temperature of air will be-
(γ=1.5,21/3=1.251)
  1. 33C
  2. 0C
  3. 21.6C
  4. 240C

A
0C
B
240C
C
33C
D
21.6C
Solution
Verified by Toppr

Given,
T1=27+273=300K
P1=2atm
γ=1.5 21/3=1.251
In the process
Tγ1Pγ11=Tγ2Pγ12
(T1T2)γ=(P2P1)γ1
(300T2)3/2=(21)1/2
T2=30021/3=2400C
The correct option is D.

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