Alcoholic NaNH,,A 105.CH,Br-CH,Br - KOH Acetylene.Here X is 1) Vinyl bromide 2) 1, 1-Dibromoethane 3) Ethyl bromide 4) Ethylene dibromide

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1,2-dibromoethane (ethylene dibromide) with alcoholic

K O H

gives :

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Give the order of reactivity towards $$SN^1$$ reactive.

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\mathrm{Br}\right)$$

ii. Isobutyl bromide Me $$_{2}$$ CHCH $$_{2}Br$$

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iv. tert-Butyl bromide $$\mathrm{Me}_{3}
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C H \equiv C H H g S O 4 - --- \to H_{2} S O_{4} (X) L i A l H_{4} - --- \to (Y) P B r_{3} - -- \to (Z)

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I n o r d e r t o c o m p l e t e t h e r e a c t i o n

1 - P e n t y n e a \to 4 - O c t a n e b \to c i s - 4 - O c t a n e a a n d b w i l l b e

(1) N a N H_{2}; a C H_{3} C H_{2} B r : H_{2} b (o n e m o l e) P d o r N i

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The IUPAC name of CH₂=CHCH₂Br is:

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