All possible number are formed using the digits $1,1,2,2,2,2,3,4,4$ taken all at a time. The number of such number in which the odd digits occupy even places is:

A

$175$

B

$162$

C

$160$

D

$180$

Medium

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Solution

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Correct option is D)

Number of such number $=_{4}C_{3}×2!3! ×2!4!6! =180$