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Aman had $128$ trading cards. He gave $\frac{3}{8}$ of his cards to Mohit and $\frac{1}{4}$ of his cards to Kushal. How many cards did he give away altogether?

$50$

$65$

$80$

$75$

Medium

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Solution

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Correct option is C)

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Abhijit spent $\frac{1}{3}$ of an hour painting his toy aeroplane and $\frac{1}{6}$ of an hour polishing his shoes. How much time did he spend together?

Easy

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The sum of two fractions is $5 \frac{1}{7}$ ,one of them is $4 \frac{1}{7}$ , what is the other fraction?

Easy

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If $\frac{x}{b + c - a} = \frac{y}{c + a - b} = \frac{z}{a + b - c}$ then show that :-

$\frac{y + z}{a} = \frac{z + x}{b} = \frac{x + y}{c}$

Medium

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What should be added to $5 \frac{3}{7}$ to get $12$

Medium

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Rohan stays in school for $8 \frac{3}{4} h o u r s$ out of which $2 \frac{1}{2} h o u r s$ are break time which include breakfast time and lunch-time. How many $h o u r s$ does he actually learns lessons in the time he is at school?

Medium

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Aman had 128 trading cards. He gave 83​ of his cards to Mohit and 41​ of his cards to Kushal. How many cards did he give away altogether?

50

65

80

75

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Aman had $128$ trading cards. He gave $\frac{3}{8}$ of his cards to Mohit and $\frac{1}{4}$ of his cards to Kushal. How many cards did he give away altogether?

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$65$

$80$

$75$

Abhijit spent $\frac{1}{3}$ of an hour painting his toy aeroplane and $\frac{1}{6}$ of an hour polishing his shoes. How much time did he spend together?

The sum of two fractions is $5 \frac{1}{7}$ ,one of them is $4 \frac{1}{7}$ , what is the other fraction?

If $\frac{x}{b + c - a} = \frac{y}{c + a - b} = \frac{z}{a + b - c}$ then show that :-

$\frac{y + z}{a} = \frac{z + x}{b} = \frac{x + y}{c}$

What should be added to $5 \frac{3}{7}$ to get $12$

Rohan stays in school for $8 \frac{3}{4} h o u r s$ out of which $2 \frac{1}{2} h o u r s$ are break time which include breakfast time and lunch-time. How many $h o u r s$ does he actually learns lessons in the time he is at school?