Among the isomeric alkanes of molecular formula C5H12, identify the one that on photochemical chlorination yields:
(i) A single monochloride
(ii) Three isomeric monochlorides
(iii) Four isomeric monochlorides.
i) To have a single mono-chloride , there should be only one type of H−atom. This is because, replacement of any H−atom leads to the formation of same product.
∴ The isomer C5H12 that leads to a single mono-chloride is neo-pentane.
CH3−CH3|C|CH3−CH3
ii) To have 3 isomeric mono-chlorides, the isomer should contain 3 different types of H−atoms.
∴ The isomer should be n−pentane.
cCH3−bCH2−aCH2−bCH2−cCH3
iii) To have 4 isomeric mono-chlorides, the isomer should contain 4 different types of H−atoms.
∴ The isomer is 2−methylbutane.