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>>Time Equations of SHM
>> $Amplitude of oscillation of a particle t$

Question

Amplitude of oscillation of a particle that executes S.H.M. is 2 cm. Its displacement from its mean position in a time equal to 1/6th of its time period is

A

$2$ cm

B

$3$ cm

C

$1 / 2$ cm

D

$1 / 3$ cm

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Solution

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Correct option is B)

$A = 2 c m$
$x = A$ $s i n$ $w t$
$= A s i n (\frac{2 π}{T} \times \frac{T}{6}) = \frac{A \times 3}{2}$
$x = 3 c m$

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