Question

An air capacitor is connected to a battery of emf V. A dielectric medium of dielectric constant K is introduced between the plates of this capacitor, with the battery still connected. The final charge on the capacitor plates relative to the previous charge

• A. is the same
• B. is more
• C. is less
• D. may be more or less depending upon the dielectric constant of the medium

Answer 1

Answer: (B)

REF.Image

Initially $Q=CV$

$=\frac{A{\epsilon }_0}{d}V$

$(k=1)$

But when dielectric

is inserted

$Q^1=K\frac{A{\epsilon }_0}{d}V$

$k>1$

so

$Q^1>Q$

(B) option is correct.