An alcohol (A) on heating with concentrated $H_{2} S O_{4}$ gives alkene (B), which shows geometrical isomerism. The compound (A) is:

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Answer 1

Since, alkene shows geometrical isomerism. So, the groups should be different on both sides of double bond.
When 2-butanol is heated with conc. sulfuric acid, it forms 2-butene, which shows geometrical isomerism in the form of cis and trans isomers.
$C H_{3} C H_{2} C H (O H) C H_{3} d e h y d r a t i o n c o n c . H_{2} S O_{4} C H_{3} C H = C H C H_{3}$

Answer 2

Since, alkene shows geometrical isomerism. So, the groups should be different on both sides of double bond.
When 2-butanol is heated with conc. sulfuric acid, it forms 2-butene, which shows geometrical isomerism in the form of cis and trans isomers.

C H_{3} C H_{2} C H (O H) C H_{3} d e h y d r a t i o n c o n c . H_{2} S O_{4} C H_{3} C H = C H C H_{3}

An alcohol (A) on heating with concentrated $H_{2} S O_{4}$ gives alkene (B), which shows geometrical isomerism. The compound (A) is:

$(C H_{3})_{2} C (O H) C H (C H_{3})_{2}$

$(C H_{3})_{2} C (O H) C H_{2} C H_{3}$

$C H_{3} C H_{2} C H (O H) C H_{3}$

All of the above

The dehydration of 1-butanol in presence of catalytic amount of concentrated $H_{2} S O_{4}$ gives:

An organic compound (A) containing C, H and O has a pleasant odour with boiling point $7 8^{0}$ . On boiling (A) with concentrated $H_{2} S O_{4}$ , colourless gas is evolved which decolorizes bromine water and alkaline $K M n O_{4}$ . The organic compound (A) is :

When excess of $C_{2} H_{5} O H$ at $14 0^{0} C$ reacts with concentrated $H_{2} S O_{4}$ , the product obtained is:

In esterification reactions, concentrated $H_{2} S O_{4}$ acts as:

Ethyl alcohol is heated with conc. $H_{2} S O_{4} .$ The product formed is:

Revise with Concepts

Chemical Properties of Alcohols and Phenols - Reactions involving cleavage of O-H bond

Chemical Properties of Alcohols - Reactions Involving Cleavage of C - O Bond

Electrophilic Aromatic Substitution Reactions in Phenols

Other reactions of Phenols

An alcohol (A) on heating with concentrated H2​SO4​ gives alkene (B), which shows geometrical isomerism. The compound (A) is:

(CH3​)2​C(OH)CH(CH3​)2​

(CH3​)2​C(OH)CH2​CH3​

CH3​CH2​CH(OH)CH3​

All of the above

The dehydration of 1-butanol in presence of catalytic amount of concentrated H2​SO4​ gives:

An organic compound (A) containing C, H and O has a pleasant odour with boiling point 780. On boiling (A) with concentrated H2​SO4​, colourless gas is evolved which decolorizes bromine water and alkaline KMnO4​. The organic compound (A) is :

When excess of C2​H5​OH at 1400C reacts with concentrated H2​SO4​, the product obtained is:

In esterification reactions, concentrated H2​SO4​ acts as:

Ethyl alcohol is heated with conc. H2​SO4​. The product formed is:

Revise with Concepts

Chemical Properties of Alcohols and Phenols - Reactions involving cleavage of O-H bond

Chemical Properties of Alcohols - Reactions Involving Cleavage of C - O Bond

Electrophilic Aromatic Substitution Reactions in Phenols

Other reactions of Phenols

An alcohol (A) on heating with concentrated $H_{2} S O_{4}$ gives alkene (B), which shows geometrical isomerism. The compound (A) is:

$(C H_{3})_{2} C (O H) C H (C H_{3})_{2}$

$(C H_{3})_{2} C (O H) C H_{2} C H_{3}$

$C H_{3} C H_{2} C H (O H) C H_{3}$

The dehydration of 1-butanol in presence of catalytic amount of concentrated $H_{2} S O_{4}$ gives:

An organic compound (A) containing C, H and O has a pleasant odour with boiling point $7 8^{0}$ . On boiling (A) with concentrated $H_{2} S O_{4}$ , colourless gas is evolved which decolorizes bromine water and alkaline $K M n O_{4}$ . The organic compound (A) is :

When excess of $C_{2} H_{5} O H$ at $14 0^{0} C$ reacts with concentrated $H_{2} S O_{4}$ , the product obtained is:

In esterification reactions, concentrated $H_{2} S O_{4}$ acts as:

Ethyl alcohol is heated with conc. $H_{2} S O_{4} .$ The product formed is: