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Question

An alcohol (A) on heating with concentrated H2SO4 gives alkene (B), which shows geometrical isomerism. The compound (A) is:
  1. (CH3)2C(OH)CH(CH3)2
  2. (CH3)2C(OH)CH2CH3
  3. CH3CH2CH(OH)CH3
  4. All of the above

A
(CH3)2C(OH)CH(CH3)2
B
(CH3)2C(OH)CH2CH3
C
CH3CH2CH(OH)CH3
D
All of the above
Solution
Verified by Toppr

Since, alkene shows geometrical isomerism. So, the groups should be different on both sides of double bond.
When 2-butanol is heated with conc. sulfuric acid, it forms 2-butene, which shows geometrical isomerism in the form of cis and trans isomers.
CH3CH2CH(OH)CH3dehydration−−−−−−conc. H2SO4CH3CH=CHCH3

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