An alcoholic drink substance pH- 4-7 then OH- ion concentration of this solution is -K-w- 10-14- mol-2-l-2-3times 10-10-5times 10-10-1times 10-10-5times 10-3-

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Toppr Admin · Accepted Answer

An alcoholic drink substance pH= 4.7 then OH− ion concentration of this solution is [Kw=10−14mol2/l2]3×10−105×10−101×10−105×10−3

An alcoholic drink substance pH= $4.7$ then $O H^{-}$ ion concentration of this solution is
[ $K_{w} = 10^{- 14} m o l^{2} / l^{2}$ ]
$3 \times 10^{- 10}$
$5 \times 10^{- 10}$
$1 \times 10^{- 10}$
$5 \times 10^{- 3}$