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An alkyl halide reacts with a group 14 element $Y$ at 570K with $C u$ as a catalyst and produces a dialkyl chloro compound $Z$ . The compound $Z$ on hydrolysis gives another compound which is a strong water repellent and quite inert chemically. The dioxide of $Y$ is acidic in nature. The alkyl halide can also be obtained from methane after monosubstitution. Identify $Y$ and $Z$ .
$Y = S i$ and $Z = (C H_{3})_{2} S i C l_{2}$
$Y = S i$ and $Z = C H_{3} C l$
$Y = C$ and $Z = S i C l_{4}$
$Y = S i$ and $Z = C C l_{4}$

A

Y = S i

and

Z = (C H_{3})_{2} S i C l_{2}

B

Y = S i

and

Z = C H_{3} C l

C

Y = C

and

Z = S i C l_{4}

D

Y = S i

and

Z = C C l_{4}

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Solution

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Monosubstitution of methane gives methyl chloride. It reacts at $570 K$ with $S i$ having $C u$ as catalyst to produce $(C H_{3})_{2} S i C l_{2}$ , which is the compound $Z$ .

$(C H_{3})_{2} S i C l_{2}$ on hydrolysis gives $(C H_{3})_{2} S i (O H)_{2}$ , which is a strong water repellent and quite inert chemically. Also $S i O_{2}$ is acidic in nature.

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