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An alloy of gold and copper weights 50 g. It contains 80% gold. How much gold should be added to the alloy so that percentage of gold is increased to 90?
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Solution
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Inital amount of gold =
$108 ×50$
$=$
$40$
gm
Let amount of gold required to me mixed =
$X$
gm
According to question ,
$40+x=109 ×$
(
$50+x$
)
Solving we get
$x=50$
gm
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