An α-particle and a proton are accelerated from rest by a potential difference of 100V. After this, their de Broglie wavelengths are λα and λp respectively. The ratio λαλp, to the nearest integer, is:
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Updated on : 2022-09-05
Solution
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Correct option is A)
We have, 21mv2=eV
De broglie wavelength= λ=mvh
λ=2meVh
λp=2(m)eVh....(1)
λα=2(4m)2eVh....(2)
Now, λαλp=8≃3
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