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Standard XII
Chemistry
Electrolytes
Question

An aqueous solution contains 0.01 M RNH2 (Kb=2×10−6) and 10−4 M NaOH.The concentration of OH− is nearly:
  1. 10−4M
  2. 1.414×10−4
  3. 2×10−4
  4. 2.414×10−4

A
2.414×10−4
B
10−4M
C
1.414×10−4
D
2×10−4
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Solution
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[OH−]⟹RNH2 is weak base, it reacts with H2O
pKb=−log10(2×10−6)=6−log2
pH=14−12(pKb−logC)
=14−12(6−log2−log10−2)
=14−3+log22+12(−2)
=10+log22
=10.150515
From, NaOH⟹[OH−]=10−4
pOH=14−pH=0.0001414⟹1.414×10−4

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