Question

Open in App

Solution

Verified by Toppr

$616>32$

$616=32×19+8$

Repeat the above step until you will get remainder as zero.

$32=8×4+0$

Since the remainder is zero, we cannot proceed further.

So, the H.C.F. of $616$ and $32$ is $8.$

Therefore, $8$ is the maximum number of columns in which they can march.

Video Explanation

Was this answer helpful?

0

0