An aromatic compound 'A' on treatment with $$CHCl_3/KOH$$ gives two compounds 'B' and 'C'. Both B and C give the same product 'D' when distilled with Zinc dust. Oxidation of D gives E having molecular formula $$C_7H_6O_2$$. The salt of E on heating with soda lime gives F which may be obtained by distilling A with zinc dust. Identify A to F.