An artificial satellite is moving in a circular orbit of radius $42250$ km. Calculate its speed if it takes $24$ hours to revolve around the earth.

Question

An artificial satellite is moving in a circular orbit of radius 42250 km- Calculate its speed it takes 24 hours to revolve around the earth-3-07  kms-1-5  kms-1-4-5  kms-1-7  kms-1-

Toppr Admin · Accepted Answer

Distance covered by the satellite in 24 hourss-2-x3C0-r-xA0- -xA0-2-xD7-3-14-xD7-42250-265464-58-xA0-kmTherefore speed of satellite-v-distance travelledtime taken-265464-5824-xD7-60-xD7-60-3-07-xA0-km-xA0-s-x2212-1

An artificial satellite is moving in a circular orbit of radius 42250 km. Calculate its speed if it takes 24 hours to revolve around the earth.
$3.07 k m s^{- 1}$
$5 k m s^{- 1}$
$4.5 k m s^{- 1}$
$7 k m s^{- 1}$

Distance covered by the satellite in $24$ hours
$s = 2 π r$
$= 2 \times 3.14 \times 42250 = 265464.58 k m$

Therefore speed of satellite,
$v = \frac{distance travelled}{time taken} = \frac{265464.58}{24 \times 60 \times 60} = 3.07 k m s^{- 1}$

An artificial satellite is moving in a circular orbit of radius 42250 km. Calculate its speed if it takes 24 hours to revolve around the earth.3.07 kms−15 kms−14.5 kms−17 kms−1

Distance covered by the satellite in 24 hourss=2πr =2×3.14×42250=265464.58 kmTherefore speed of satellite,v=distance travelledtime taken=265464.5824×60×60=3.07 km s−1

An artificial satellite is moving in a circular orbit of radius 42250 km. Calculate its speed if it takes 24 hours to revolve around the earth.
$3.07 k m s^{- 1}$
$5 k m s^{- 1}$
$4.5 k m s^{- 1}$
$7 k m s^{- 1}$

Distance covered by the satellite in $24$ hours
$s = 2 π r$
$= 2 \times 3.14 \times 42250 = 265464.58 k m$

Therefore speed of satellite,
$v = \frac{distance travelled}{time taken} = \frac{265464.58}{24 \times 60 \times 60} = 3.07 k m s^{- 1}$