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Updated on : 2022-09-05

Solution

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Correct option is A)

$21 mv_{1}+(−10RGmM_{e} )=21 mv_{2}+(−RGmM_{e} )$

Given $v_{1}=12Km/s$

$v_{1}=12000m/s$

$M_{e}=$ Mass of earth

From above equation

$21 m(v_{2}−v_{1})=(RGMe −10RGme ).m$

$[v_{1}−(12000)_{2}]=59 RGMe =59 R_{2}6Me .R$

$=59 .g.R=59 ×9.8×6400000$

$v_{1}−12000_{2}=112896000$

$v_{2}=16031.57m/s$

$v_{2}=16km/s$

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