An athlete completes one round of a circle track of radius $R$ in $40$ seconds. What will be the displacement at the end of $2$ minutes $20$ seconds:

Question

An athlete completes one round of a circle track of radius R in 40 seconds- What will be the displacement the end of 2 minutes 20 seconds-Zero2R2pi R7pi R

Toppr Admin · Accepted Answer

Total time duration in consideration -2-xA0-min-xA0-20-xA0-sec-140-xA0-secHe completed 1 round in 40 secIn 140 sec- he will cover -14040-3-5-xA0-roundsAfter 3-5 rounds- he would be on the opposite side of the starting pointSo- the displacement will be the diameter or 2R-

An athlete completes one round of a circle track of radius $R$ in $40$ seconds. What will be the displacement at the end of $2$ minutes $20$ seconds:
$Z e r o$
$2 R$
$2 π R$
$7 π R$

Total time duration in consideration $= 2 m i n 20 s e c = 140 s e c$
He completed 1 round in 40 sec
In 140 sec, he will cover $= \frac{140}{40} = 3.5 r o u n d s$
After 3.5 rounds, he would be on the opposite side of the starting point
So, the displacement will be the diameter or $2 R$ .

An athlete completes one round of a circle track of radius R in 40 seconds. What will be the displacement at the end of 2 minutes 20 seconds:Zero2R2πR7πR

Total time duration in consideration =2 min 20 sec=140 secHe completed 1 round in 40 secIn 140 sec, he will cover =14040=3.5 roundsAfter 3.5 rounds, he would be on the opposite side of the starting pointSo, the displacement will be the diameter or 2R.

An athlete completes one round of a circle track of radius $R$ in $40$ seconds. What will be the displacement at the end of $2$ minutes $20$ seconds:
$Z e r o$
$2 R$
$2 π R$
$7 π R$

Total time duration in consideration $= 2 m i n 20 s e c = 140 s e c$
He completed 1 round in 40 sec
In 140 sec, he will cover $= \frac{140}{40} = 3.5 r o u n d s$
After 3.5 rounds, he would be on the opposite side of the starting point
So, the displacement will be the diameter or $2 R$ .