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Question

An earth satelites S has orbit radius which 4 times that of communication satellite C. The period of revolution of S will be.
  1. 32 days
  2. 8 days
  3. 18 days
  4. 9 days

A
9 days
B
18 days
C
8 days
D
32 days
Solution
Verified by Toppr

Larger the distance of planet from the sun, larger will be its period of revolution around the sun.
Kepler's third low planetary motion the square of the period of revolution of any planet around the sun is directly proportional to the cube of the semi-major axis of its elliptical orbit.
T2R3
TsTc=(RsRc)3/2
given Rs=4Rc
TsTc(4RcRc)3/2=8
for Tc=1day
Ts=8 days.

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