An electric bulb is made of tungsten filament of resistance $R Ω$ . It is marked $100 W$ and $230 V$ . Then, the value of $R$ is :
$739 Ω$
$300 Ω$
$100 Ω$
$529 Ω$

Question

An electric bulb is made of tungsten filament of resistance ROmega- It is marked 100W and 230 V- Then- the value of R is -739 Omega300 Omega100 Omega529 Omega

Toppr Admin · Accepted Answer

Power P-Vi-V2RR-V2P-230-2100-529-x3A9-

An electric bulb is made of tungsten filament of resistance RΩ. It is marked 100W and 230V. Then, the value of R is :739Ω300Ω100Ω529Ω

Power P=Vi=V2RR=V2P=(230)2100=529Ω

An electric bulb is made of tungsten filament of resistance $R Ω$ . It is marked $100 W$ and $230 V$ . Then, the value of $R$ is :
$739 Ω$
$300 Ω$
$100 Ω$
$529 Ω$

Power $P = V_{i} = \frac{V^{2}}{R}$
$R = \frac{V^{2}}{P} = \frac{(230)^{2}}{100} = 529 Ω$