An electric bulb works on 230 V line and draws 0-1 A current- The resistance of the filament is-230 Omega 2300 Omega 23 Omega 2-3 Omega

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Toppr Admin · Accepted Answer

Voltage- V-230-xA0-VCurrent- I-0-1-xA0-AAccording to Ohm-apos-s law-V-IR-x21D2-R-VI-xA0-xA0-xA0-xA0- -xA0-xA0-xA0-xA0-xA0-xA0- -2300-1-x21D2-R-2300-xA0-x3A9-

An electric bulb works on $230 V$ line and draws $0.1 A$ current. The resistance of the filament is:
$230 Ω$
$2300 Ω$
$23 Ω$
$2.3 Ω$

Voltage, $V = 230 V$
Current, $I = 0.1 A$
According to Ohm's law,
$V = I R$
$\Rightarrow R = \frac{V}{I}$

$= \frac{230}{0.1}$
$\Rightarrow R = 2300 Ω$

An electric bulb works on 230 V line and draws 0.1 A current. The resistance of the filament is:230 Ω2300 Ω23 Ω2.3 Ω

Voltage, V=230 VCurrent, I=0.1 AAccording to Ohm's law,V=IR⇒R=VI =2300.1⇒R=2300 Ω

An electric bulb works on $230 V$ line and draws $0.1 A$ current. The resistance of the filament is:
$230 Ω$
$2300 Ω$
$23 Ω$
$2.3 Ω$

Voltage, $V = 230 V$
Current, $I = 0.1 A$
According to Ohm's law,
$V = I R$
$\Rightarrow R = \frac{V}{I}$

$= \frac{230}{0.1}$
$\Rightarrow R = 2300 Ω$