An electric charge 10−3μC is placed at the origin (0, 0) of X-Y co-ordinate system. Two points A and B are situated at (2,2) and (2, 0) respectively. The potential difference between the points A and B will be :
Open in App
Verified by Toppr
Correct option is
The distance of point A from origin is rA=(2−0)2+(2−0)2=4=2 The distance of point B from origin is rB=(2−0)2+(0−0)2=4=2 Potential at A due to charge Q=10−3μC is VA=4πϵ0rAQ=8πϵ0Q as rA=2 and potential at B is VB=4πϵ0rBQ=8πϵ0Q as rB=2 Potential difference between A and B =VA−VB=8πϵ0Q−8πϵ0Q=0 volt.